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x^2-15.35x-102.12=0
a = 1; b = -15.35; c = -102.12;
Δ = b2-4ac
Δ = -15.352-4·1·(-102.12)
Δ = 644.1025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15.35)-\sqrt{644.1025}}{2*1}=\frac{15.35-\sqrt{644.1025}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15.35)+\sqrt{644.1025}}{2*1}=\frac{15.35+\sqrt{644.1025}}{2} $
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